Area of traingle ABC whose sides are 24m, 40m and 32m is-

96 m^{2}

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384 m^{2}

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43 m^{2}

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192 m^{2}

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Solution

The correct option is B $384 m^{2}$
Area of triangle with sides $a$ , $b$ and $c$ and $s$ $= \frac{a + b + c}{2}$ is $\sqrt{s (s - a) (s - b) (s - c)}$ .
For triangle with sides 24 m, 40 m and 32 m, $s = \frac{24 + 40 + 32}{2} = 48 m$
Area of the triangle with sides 24 m, 40 m and 32 m $= \sqrt{48 (48 - 24) (48 - 40) (48 - 32)} = \sqrt{48 \times 24 \times 8 \times 16} = \sqrt{24 \times 2 \times 24 \times 8 \times 8 \times 2} = 24 \times 8 \times 2 = 384 m^{2}$
Hence, option 'B' is correct.

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