Question

Area of $△ABC=68.2sqm$. Find the area of shaded region

Answer 1

$\begin{array}{c}Lettriangleareequillateral\\ \Rightarrow Areaofequilateraltriangle=\frac{\sqrt{3}}{4}\times {\left(side\right)}^2\\ \Rightarrow 68.2sqm=0.43{\left(side\right)}^2\\ \Rightarrow \sqrt{158.6}=side,side=12.6m\\ \Rightarrow Ar\Delta BDC=\frac{1}{2}\times 12.6\times 4.21=26.51m^2\\ \Rightarrow Areaofshaded=\left(68.2-26.51\right)=41.69m^{2}Ans.\end{array}$