Question

Area of triangle ABC whose sides are $24$m, $40$m and $32$m is

• A. $96m^2$
• B. $384m^2$
• C. $43m^2$
• D. $192m^2$

Answer 1

The correct option is B $384m^2$

S=a+b+c2=24+40+322=962=48S=a+b+c2=24+40+322=962=48m
Area of ΔΔABC=S(S−a)(S−b)(S−c)−−−−−−−−−−−−−−−−−−√=S(S−a)(S−b)(S−c)
=48(48−24)(48−40)(48−32)−−−−−−−−−−−−−−−−−−−−−−−√=48(48−24)(48−40)(48−32)
=48×24×8×16−−−−−−−−−−−−−√=48×24×8×16
=24×2×24×8×16−−−−−−−−−−−−−−−−√=24×2×24×8×16
=24×16×16−−−−−−−−−−√=24×16=24×16×16=24×16
=384m2