Area of triangle PQR is 100 cm $^{2}$ . If altitude QN is 10 cm, then its base PR is

15 cm

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5 cm

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10 cm

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20 cm

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Solution

The correct option is D 20 cm
Area of a triangle = $\frac{1}{2}$ × base × height
Here, altitude (height) = $10$ cm and area = $100$ cm $^{2}$

Since, area = $\frac{1}{2}$ × base × height
So, 100 = $\frac{1}{2}$ × base × 10
Therefore, base = $\frac{100 \times 2}{10}$ = $20$ cm

Hence, the base of the given triangle is $20$ cm.

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Question 15

Area of $Δ P Q R$ is $100 c m^{2}$ as shown in the figure below. If altitude QT is 10 cm, then its base PR is

(a) 20 cm
(b) 15 cm
(c) 10 cm
(d) 5 cm

The area of triangle

P Q R

100 c m^{2}

(figure). If altitude

Q T

10 c m

, then its base

P R

is:

The area of triangle PQR is $ 100 c{m}^{2}$ (figure). If altitude QT is $ 10 cm$, then its base PR is (a) $ 20 cm$ (b) $ 15 cm$ (c) $ 10 cm$ (d) $ 5 cm$

Q. In the given figure, if the area of triangle

P Q R

100 c m^{2}

and the altitude

Q T

10 c m

, then find the value of PR. [2 marks]

Area of $Δ P Q R$ is $100 c m^{2}$ as shown in the figure below. If altitude QT is 10 cm, then its base PR is

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Area of triangle PQR is 100 cm2. If altitude QN is 10 cm, then its base PR is

The correct option is D 20 cmArea of a triangle = 12 × base × height Here, altitude (height) = 10 cm and area = 100 cm2 Since, area = 12 × base × height So, 100 = 12 × base × 10 Therefore, base = 100×210 = 20 cm Hence, the base of the given triangle is 20 cm.

Area of triangle PQR is 100 cm $^{2}$ . If altitude QN is 10 cm, then its base PR is