Question

Area under the curve $y=\sqrt{3x+4}$ between x=0 and x=4 is

• A. $\frac{56}{9}sq.unit$
• B. $\frac{64}{9}sq.unit$
• C. $8sq.unit$
• D. $Noneofthese$

Answer 1

The correct option is D $Noneofthese$

Area =${\int }_0^4\sqrt{3x+4}dx={\left|\frac{(3x+4{)}^{\frac{3}{2}}}{3.\left(\frac{3}{2}\right)}\right|}_0^4$


$=\frac{2}{9}\times 56=\frac{112}{9}$ sq.unit