Question

Area under the curve $y=x^2-4x$ within the x-axis and the line x=2, is

• A. $\frac{16}{3}sq.unit$
• B. $-\frac{16}{3}sq.unit$
• C. $\frac{4}{7}sq.unit$
• D. $Cannotbecalculated$

Answer 1

The correct option is A $\frac{16}{3}sq.unit$

${\int }_0^2(-x^2+4x)dx={[-\frac{x^3}{3}+\frac{4x^2}{2}]}_0^2=\frac{16}{3}$ sq. unit.