Areas of two similar triangles are $225 s q . c m$ and $81 s q c m$ . If a side of the smaller triangle is $12 c m$ , then find corresponding side of the bigger triangle.

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Solution

If two triangle is similar then,
$\begin{matrix} \frac{a r e a o f Δ 1}{a r e a o f Δ 2} = {(\frac{s i d e o f Δ 1}{s i d e o f Δ 2})}^{2} \frac{225}{81} = {(\frac{x}{12})}^{2} = x = 12 \times \sqrt{\frac{225}{81}} = 12 \times \frac{15}{9} = 20 c m \end{matrix}$

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Areas of two similar triangles are 225 sq.cm and 81 sq cm. If a side of the smaller triangle is 12 cm, then find corresponding side of the bigger triangle.

If two triangle is similar then,areaofΔ1areaofΔ2=(sideofΔ1sideofΔ2)222581=(x12)2=x=12×√22581=12×159=20cm

Areas of two similar triangles are $225 s q . c m$ and $81 s q c m$ . If a side of the smaller triangle is $12 c m$ , then find corresponding side of the bigger triangle.

If two triangle is similar then,
$\begin{matrix} \frac{a r e a o f Δ 1}{a r e a o f Δ 2} = {(\frac{s i d e o f Δ 1}{s i d e o f Δ 2})}^{2} \frac{225}{81} = {(\frac{x}{12})}^{2} = x = 12 \times \sqrt{\frac{225}{81}} = 12 \times \frac{15}{9} = 20 c m \end{matrix}$