Argument of the complex number i-2 - 2-i is where i - - - 1- - i-2 - 2-i - - - - - - i - - - 1

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Logarithm of a Complex Number

Argument of t...

Question

Argument of the complex number $(\frac{i}{2} - \frac{2}{i})$ is (where $i = \sqrt{- 1}$ )

सम्मिश्र संख्या $(\frac{i}{2} - \frac{2}{i})$ के कोणांक का मान है (यहाँ $i = \sqrt{- 1}$ )

\frac{π}{4}

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\frac{π}{2}

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\frac{3 π}{4}

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∣ ∣ ∣ ∣ ∣ \frac{\sqrt{3} + i}{{[1 + \frac{1}{(1 - i)}]}^{2}} ∣ ∣ ∣ ∣ ∣

i = \sqrt{- 1}

∣ ∣ ∣ ∣ ∣ \frac{\sqrt{3} + i}{{[1 + \frac{1}{(1 - i)}]}^{2}} ∣ ∣ ∣ ∣ ∣

i = \sqrt{- 1}

z = \frac{2 + i}{4 i + {(1 + i)}^{2}},

i = \sqrt{- 1}

\frac{{(1 + i)}^{5} {(1 + \sqrt{3 i})}^{2}}{- 2 i (- \sqrt{3} + i)}

The principal argument of the complex number $\frac{2 + i}{4 i + (1 + i)^{2}},$ ( where $i = \sqrt{- 1}$ ) is

| z | = \sqrt{a^{2} + b^{2}}

arg (z) = {tan}^{- 1} \frac{b}{a}

| z | = \sqrt{a^{2} + b^{2}}

arg (z) = {tan}^{- 1} \frac{b}{a}

z = \frac{(1 + i) (\sqrt{3} - i)}{\sqrt{3} + i}

z = \frac{(1 + i) (\sqrt{3} - i)}{\sqrt{3} + i}

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