Arithmetic means between 4 and 12 are and .
The common difference is given by d=(b−a)(n+1). The resulting AP is a, a+d, a+ (2×d),...., a+(n×d) ,b. Given, a = 4, b = 12, n = 3. Therefore d=(12−4)(3+1)=2 ∴The resulting sequence is 4, 6, 8, 12
Insert three arithmetic means between 4 and 12.