Arpit and Rita will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Arpit and Rita have an equal chance of choosing any one of the hand signs, what is the probability that Arpit will win?

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Solution

The correct option is D
No matter what sign Arpit throws, there is one sign Rita could throw that would beat it, one that would tie, and one that would lose. Rita is equally likely to throw any one of the three signs. Therefore, the Probability that Arpit will win is $\frac{1}{3}$

Probability that Rita will win = $\frac{1}{3}$

Probability of a tie = $\frac{1}{3}$ .

Probability that Arpit will win = $\frac{1}{3}$

The correct answer is (d).

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