Arrange 4d,5p,5f and 6p orbitals in decreasing order of their energies:
A
5f>6p>5p>4d
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B
6p>5f>5p>4d
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C
6p>5f>4d>5p
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D
5f>6p>4d>5p
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Solution
The correct option is A5f>6p>5p>4d Higher the n+l value, higher id the energy. (n+l) values for : 4d=4+2=6 5p=5+1=6 5f=5+3=8 6p=6+1=7
If (n+l) values are same, then higher value of n will have more energy. So, 5p has more energy than 4d
∴ Correct order of energy would be 5f>6p>5p>4d
Correct option is A