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Question

Arrange 4d,5p,5f and 6p orbitals in decreasing order of their energies:

A
5f>6p>5p>4d
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B
6p>5f>5p>4d
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C
6p>5f>4d>5p
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D
5f>6p>4d>5p
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Solution

The correct option is A 5f>6p>5p>4d
Higher the n+l value, higher id the energy.
(n+l) values for :
4d=4+2=6
5p=5+1=6
5f=5+3=8
6p=6+1=7
If (n+l) values are same, then higher value of n will have more energy. So, 5p has more energy than 4d
∴ Correct order of energy would be 5f>6p>5p>4d
Correct option is A

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