Arrange A, B, C, D in ascending order A) Maximum value of sin5x B) Minimum value of x+1x(x>0) C) Minimum value of 4×2(x2−3)3+27 D) Minimum value of 5sin2x+3cos2x
A
A, B, D,C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
A, C, B, D
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
A, D, B, C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
B, D, A, C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C A, B, D,C (A) f(x)=sin5x f(x)max=1 (B) Use AM & GM x+1x2≥(1)12
x+1x≥2
(C) f(x)=4×2(x2−3)3+27
f(√3) is minimum value f(√3)=4×227 (D) f(x)=2sinx2x+3 fmin(x)=3 when sinx=0