Arrange acidity of given four compounds in decreasing order-I CH3COOH II CH3-CNIII CH- CH IV CH3-CHOSelect the correct answer from the codes given below-

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Chemical Reactions

Arrange acidi...

Question

Arrange acidity of given four compounds in decreasing order:
(I) $C H_{3} C O O H$ (II) $C H_{3} - C N$
(III) $C H \equiv C H$ (IV) $C H_{3} - C H O$
Select the correct answer from the codes given below.

I > I V > I I I > I I

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I > I V > I I > I I I

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I I I > I > I V > I I

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I I > I V > I > I I I

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Solution

The correct option is B $I > I V > I I > I I I$
As conjugate base is more stable, more is the acidic strength increases.
Therefore, acidic strength order:
$C H_{3} C O O H > C H_{3} C H O > C H_{3} - C \equiv N > H C \equiv C H$
So, $I > I V > I I > I I I$

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Arrange acidity of given four compounds in decreasing order:(I) CH3COOH (II) CH3−CN(III) CH≡CH (IV) CH3−CHOSelect the correct answer from the codes given below.

The correct option is B I>IV>II>IIIAs conjugate base is more stable, more is the acidic strength increases.Therefore, acidic strength order:CH3COOH>CH3CHO>CH3−C≡N>HC≡CHSo, I>IV>II>III

Arrange acidity of given four compounds in decreasing order:
(I) $C H_{3} C O O H$ (II) $C H_{3} - C N$
(III) $C H \equiv C H$ (IV) $C H_{3} - C H O$
Select the correct answer from the codes given below.

The correct option is B $I > I V > I I > I I I$
As conjugate base is more stable, more is the acidic strength increases.
Therefore, acidic strength order:
$C H_{3} C O O H > C H_{3} C H O > C H_{3} - C \equiv N > H C \equiv C H$
So, $I > I V > I I > I I I$