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Question

Arrange acidity of given four compounds in decreasing order:
(I) CH3COOH (II) CH3CN

(III) CHCH (IV) CH3CHO
Select the correct answer from the codes given below.

A
I>IV>III>II
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B
I>IV>II>III
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C
III>I>IV>II
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D
II>IV>I>III
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Solution

The correct option is B I>IV>II>III
As conjugate base is more stable, more is the acidic strength increases.
Therefore, acidic strength order:
CH3COOH>CH3CHO>CH3CN>HCCH
So, I>IV>II>III

983895_130108_ans_258c17aef4024220b725af8624e7aef5.PNG

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