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Question

Arrange AgF, AgCl, AgBr and AgI in the increasing order of solubility in water.


A
AgBr<AgI<AgCl<AgF
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B
AgI<AgBr<AgCl<AgF
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C
AgI<AgCl<AgBr<AgF
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D
None of the above
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Solution

The correct option is A $$AgI < AgBr < AgCl < AgF$$
The increasing order of the solubility of silver halides in water is $$AgI < AgBr < AgCl < AgF$$. This is due to an increase in the hydration energy and decrease in the lattice energy in the same order.

Chemistry

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