Question

# Arrange AgF, AgCl, AgBr and AgI in the increasing order of solubility in water.

A
AgBr<AgI<AgCl<AgF
B
AgI<AgBr<AgCl<AgF
C
AgI<AgCl<AgBr<AgF
D
None of the above

Solution

## The correct option is A $$AgI < AgBr < AgCl < AgF$$The increasing order of the solubility of silver halides in water is $$AgI < AgBr < AgCl < AgF$$. This is due to an increase in the hydration energy and decrease in the lattice energy in the same order.Chemistry

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