Arrange AgF, AgCl, AgBr and AgI in the increasing order of solubility in water.

A g B r < A g I < A g C l < A g F

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A g I < A g B r < A g C l < A g F

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A g I < A g C l < A g B r < A g F

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None of the above

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Solution

The correct option is A $A g I < A g B r < A g C l < A g F$
The increasing order of the solubility of silver halides in water is $A g I < A g B r < A g C l < A g F$ . This is due to an increase in the hydration energy and decrease in the lattice energy in the same order.

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