Arrange benzene, n-hexane and ethyne in decreasing order of acidic behaviour. Also give reason for this behaviour.

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Solution

The decreasing order of acidic behavior is $H C \equiv C H > C_{6} H_{6} > C_{6} H_{14}$ .
Due to maximum $s$ orbital character in ethyne (50 %) as compared to 33% in benzene and 25% in n-hexane.

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Arrange benzene, n-hexane and ethyne in decreasing order of acidic behaviour. Also give reason for this behaviour.

The decreasing order of acidic behavior is HC≡CH>C6H6>C6H14.Due to maximum s orbital character in ethyne (50 %) as compared to 33% in benzene and 25% in n-hexane.

The decreasing order of acidic behavior is $H C \equiv C H > C_{6} H_{6} > C_{6} H_{14}$ .
Due to maximum $s$ orbital character in ethyne (50 %) as compared to 33% in benzene and 25% in n-hexane.