Question

Arrange $-\frac{5}{9},\frac{7}{12},-\frac{2}{3}$ and $\frac{11}{18}$ in ascending order of their magnitudes. Identify the smallest

Answer 1

Consider the given numbers $-\frac{5}{9},\frac{7}{12},-\frac{2}{3}$ and $\frac{11}{18}$.

The LCM of the denominators $9,12,3,18$ is $36$. Therefore, the given numbers will be:

$-\frac{5\times 4}{9\times 4}=-\frac{20}{36}\frac{7\times 3}{12\times 3}=\frac{21}{36}-\frac{2\times 12}{3\times 12}=-\frac{24}{36}\frac{11\times 2}{18\times 2}=\frac{22}{36}$

Thus, the numbers in ascending order are shown below:

$-\frac{24}{36},-\frac{20}{36},\frac{21}{36},\frac{22}{36}\Rightarrow -\frac{2}{3},-\frac{5}{9},\frac{7}{12},\frac{11}{18}$