Question

Arrange following oxides in increasing acidic nature.
$L{i}_{2}O,BeO,B_2{O}_3$

• A. $L{i}_{2}O<BeO<B_2{O}_3$
• B. $BeO<L{i}_{2}O<B_2{O}_3$
• C. $L{i}_{2}O<B_2{O}_3<BeO$
• D. None of these

Answer 1

The correct option is A $L{i}_{2}O<BeO<B_2{O}_3$

$L{i}_{2}O<BeO<B_2{O}_3$
Li and Be are metal so its oxide will be basic.
Boron oxide is acidic.
Now metallic nature decreases down the period so the basic nature of oxide will decrease. Hence $BeO>L{i}_{2}O$.