Arrange I Ce 3- II La 3- III P m 3- and IV Y b 3- in increasing order of their ionic radiiA- IV - III - I - IIB- I - IV - III - IIC- IV - III - II - ID- III - II - I - IV

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Byju's Answer

Standard XII

Chemistry

Physical Properties (Group 1)

Arrange I Ce ...

Question

Arrange (I) $C e^{3 +}$ , (II) $L a^{3 +}$ , (III) $P m^{3 +}$ and (IV) $Y b^{3 +}$ in increasing order of their ionic radii

I V < I I I < I < I I

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I < I V < I I I < I I

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I V < I I I < I I < I

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I I I < I I < I < I V

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Solution

The correct option is A $I V < I I I < I < I I$
Atomic radii decreases across the lanthanide series. As all the ions are in +3 oxidation state, ionic radii will follow the trend of atomic radii.
$L a^{+ 3} I I > C e^{+ 3} I > P m^{+ 3} I I I > Y b^{+ 3} I V$

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Arrange (I) Ce3+, (II) La3+, (III) Pm3+ and (IV) Yb3+ in increasing order of their ionic radii

The correct option is A IV<III<I<IIAtomic radii decreases across the lanthanide series. As all the ions are in +3 oxidation state, ionic radii will follow the trend of atomic radii. La+3II>Ce+3I>Pm+3III>Yb+3IV

Arrange (I) $C e^{3 +}$ , (II) $L a^{3 +}$ , (III) $P m^{3 +}$ and (IV) $Y b^{3 +}$ in increasing order of their ionic radii

The correct option is A $I V < I I I < I < I I$
Atomic radii decreases across the lanthanide series. As all the ions are in +3 oxidation state, ionic radii will follow the trend of atomic radii.
$L a^{+ 3} I I > C e^{+ 3} I > P m^{+ 3} I I I > Y b^{+ 3} I V$