Question

Question 109.
Arrange in ascending order.
0.011, 1.001, 0.101, 0.110

Answer 1

Given numbers re 0.011, 1.001, 0.101 and 0.110.
$\begin{array}{c}\therefore 0.011=0+\frac{0}{10}+\frac{1}{100}+\frac{1}{1000}\\ 1.001=1+\frac{0}{10}+\frac{0}{100}+\frac{1}{1000}\\ 0.101=0+\frac{1}{10}+\frac{0}{100}+\frac{1}{1000}\\ 0.110=0+\frac{1}{10}+\frac{1}{100}+\frac{0}{1000}\end{array}$
Here, the whole number part of 1.001 is greater than 0.011, 0.101 and 0.110.
Now, tenths part of 0.011 = $\frac{0}{10}$
Tenths part of 0.101 = $\frac{1}{10}$
and tenths part of 0.110 = $\frac{1}{10}$
$\therefore$ 0.011 < 0.101 and 0.011 < 0.110
Again, hundredths part of 0.101 = $\frac{0}{100}$
and hundredths part of 0.110 = $\frac{1}{100}$
$\therefore$ 0.101 < 0.110
Hence, the ascending order of given numbers are
0.011 < 0.101 < 0.110 < 1.001