Question

Arrange in ascending order :

$\frac{8}{13},\frac{8}{9},\frac{8}{15},\frac{8}{11},\frac{8}{17}$

Answer 1

Given, fraction is $\frac{8}{13},\frac{8}{9},\frac{8}{15},\frac{8}{11},\frac{8}{17}$

We know that for the fraction having same numerator, the fraction which has greater denominator be smaller as compare to fractions having smaller denominator.

Since, $9<11<13<15<17$

Hence, ascending order of $\frac{8}{13},\frac{8}{9},\frac{8}{15},\frac{8}{11},\frac{8}{17}$ will be $\frac{8}{17}<\frac{8}{15}<\frac{8}{13}<\frac{8}{11}<\frac{8}{9}$.