The correct option is A (ii) > (iii) > (i) > (iv)
Electron donating substituents on benzene will increase the electron density on benzene and activates the ring toward aromatic electrophilic substitution.
NH2 is a strong electron donating group showing +R effect. Hence, compound (ii) is most reactive towards SE reaction.
NH+3 group is a strong electron withdrawing group with -I and -R effect. Hence, it reduce electron density on benzene and deactivates the ring. Hence, it is least reactive toward SE reaction.
In Bromobenzene, Br show both -I and +R effect. But -I effect is dominating so it will have less electron on ring than (ii) and (iii).
Toluene shows +I and +H effect. This increase electron density on benzene more than (i).
Hence, the decreasing trend toward SE reaction is
(ii) > (iii) > (i) > (iv)