Arrange in the order of increasing basicity $(N O_{2}, K_{2} O, Z n O)$ :

N O_{2} < Z n O < K_{2} O

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K_{2} O < Z n O < N O_{2}

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N O_{2} < K_{2} O < Z n O

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K_{2} O < N O_{2} < Z n O

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Solution

The correct option is A $N O_{2} < Z n O < K_{2} O$
As the electronegativity of an element increases, the basic character of oxides decreases.

The increasing order of electronegativity is $K < Z n < N$

Hence, the increasing order of basicity is $N O_{2} < Z n O < K_{2} O$ .

Hence, the correct option is $A$

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