Arrange $O H C H_{2} C O O H (I),$ $H O C H_{2} C H_{2} C O O H (I I)$ and $C H_{3} C O O H (I I I)$ in order of their acidic strength.

I > I I > I I I

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I I I > I I > I

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I > I I I > I I

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I I > I I I > I

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Solution

The correct option is A $I > I I > I I I$

$\Rightarrow$ Electron withdrawing group increases acidity.
$\Rightarrow$ When distance of electron withdrawing group increases from $- C O O H$ group, acidic strength decreases.
$\Rightarrow$ Electron releasing group $(- C H_{3})$ decreases acidity.
Therefore correct order is $I > I I > I I I$ .
Hence correct option is (a).

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