Arrange S,O and Se in ascending order of their electron affinity.
A
Se<S<O
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B
O<Se<S
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C
S<O<Se
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D
S<Se<O
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Solution
The correct option is BO<Se<S Se,S and O are members of group 16. Now in a group electron affinity decreases down a group. therefore, the electron affinity of S is more than oxygen due to small size of oxygen.
Addition of extra electron to the oxygen causes more inter-electronic repulsion and electron affinity decreases.