Arrange stability of the given carbocations in decreasing order.

I > I I > I I I > I V

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I I I > I I > I > I V

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I V > I > I I > I I I

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I I > I I I > I > I V

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Solution

The correct option is D $I I > I I I > I > I V$
The carbocation here is stabilized when there is an electron-donating group present.
More the activating effect of the group, more stable is the cation. Out of given options, $I I$ is most stable due to ability of oxygen to activate the ring with its lone pair of electrons.
Out of $I I I$ and $I, I I I$ is more stable as the lone pair of nitrogen in $I$ is less available due to $A c$ group. $I V$ is least stable due to electron- withdrawing effect of $C l$ atom.
$∴$ Order of stability= $I I > I I I > I > I V$

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50^{\circ}

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