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Question


Arrange the above in the correct order of enol content :
1182433_0a04dc2f38c140b69b174c874fdf6d2b.png

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Solution

The enol formed in case III will have a substituted double bond - more no. of hyperconjugative structure than both I & II
In I case, the enol formed is lacking hydrogen bonding. So, I has the last enol content.
Hence, the order is -
III>II>I

1376346_1182433_ans_8f647d707be84e159ca50f556e57413a.png

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