Arrange the carbanions (CH3)3C−,Cl3C−,(CH3)2HC−,C6H5H2C− in order of their decreasing stability :
A
(CH3)2HC−>Cl3C−>C6H5H2C−>(CH3)3C−
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B
Cl3C−>C6H5H2C−>(CH3)2HC−>(CH3)3C−
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C
(CH3)3C−>(CH3)2HC−>C6H5H2C−>Cl3C−
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D
C6H5H2C−>Cl3C−>(CH3)3C−>(CH3)2HC−
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Solution
The correct option is BCl3C−>C6H5H2C−>(CH3)2HC−>(CH3)3C−
1. (CH3)3C− is the least stable as it supply more electrons +I to the carbanion.
2. (CH3)2HC− is stable than (CH3)3C− as it has less +I effect compared to the other. But still it is less stable than the others, the reason being the same as above.
3.C6H5H2C− is a resonating structure. Normally resonance effect is more compared to other effects. But since Cl3C− has 3Cl group −I effect, inductive effect overruns resonance effect.