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Question

Arrange the carbanions (CH3)3C−,Cl3C−,(CH3)2HC−,C6H5H2C− in order of their decreasing stability :

A
(CH3)2HC>Cl3C>C6H5H2C>(CH3)3C
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B
Cl3C>C6H5H2C>(CH3)2HC>(CH3)3C
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C
(CH3)3C>(CH3)2HC>C6H5H2C>Cl3C
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D
C6H5H2C>Cl3C>(CH3)3C>(CH3)2HC
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Solution

The correct option is B Cl3C>C6H5H2C>(CH3)2HC>(CH3)3C
1. (CH3)3C is the least stable as it supply more electrons +I to the carbanion.
2. (CH3)2HC is stable than (CH3)3C as it has less +I effect compared to the other. But still it is less stable than the others, the reason being the same as above.
3.C6H5H2C is a resonating structure. Normally resonance effect is more compared to other effects. But since Cl3C has 3 Cl group I effect, inductive effect overruns resonance effect.

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