Arrange the carbon ions, $(C H_{3})_{3} ¯ C, ¯ C C l_{3}, (C H_{3})_{2} ¯ C H, C_{6} H_{5} ¯ C C H_{2}$ in order of their decreasing stability.

(C H_{3})_{2} ¯ C H > C C l_{3} > C_{6} H_{5} ¯ C H_{2} > (C H_{3})_{3} ¯ C

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¯ C C l_{3} > C_{6} H_{5} ¯ C H_{2} > (C H_{3})_{2} ¯ C H > (C H_{3})_{3} ¯ C

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(C H_{3})_{3} ¯ C > (C H_{3})_{2} ¯ C H > C_{6} H_{5} ¯ C H_{2} > ¯ C C l_{3}

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C_{6} H_{5} ¯ C H_{2} > ¯ C C l_{3} > (C H_{3})_{3} ¯ C > (C H_{3})_{2} ¯ C H

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Solution

The correct option is C $¯ C C l_{3} > C_{6} H_{5} ¯ C H_{2} > (C H_{3})_{2} ¯ C H > (C H_{3})_{3} ¯ C$
The decreasing order for the stability of carbanion is $¯ C C l_{3} > C_{6} H_{5} ¯ C H_{2} > (C H_{3})_{2} ¯ C H > (C H_{3})_{3} ¯ C$
$¯ C C l_{3}$ is most stable as electron withdrawing chlorine atoms decrease the electron density on negatively charged C atom. $C_{6} H_{5} ¯ C H_{2}$ is also stable as the negative charge is delocalised over benzene ring and is dispersed. $(C H_{3})_{3} ¯ C$ is least stable as 3 methyl groups increase the electron density (through +I effect) on negatively charged C atom.

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Similar questions

(C H_{3})_{3} ¯ C, ¯ C C l_{3}, (C H_{3})_{2} ¯ C H, C_{6} H_{5} ¯ C H_{2}

(C H_{3})_{3} ¯ ¯¯ ¯ C, ¯ ¯¯ ¯ C C l_{3}, (C H_{3})_{2} ¯ ¯¯ ¯ C H, C_{6} H_{5} ¯ ¯¯ ¯ C H_{2}

(C H_{3})_{3} C^{-}, C l_{3} C^{-}, (C H_{3})_{2} H C^{-}, C_{6} H_{5} H_{2} C^{-}

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