Arrange the $C e^{+ 3}, L a^{+ 3}, P m^{+ 3} a n d Y b^{+ 3}$ in increasing order of their ionic radii:

Y b^{+ 3} < P m^{+ 3} < C e^{+ 3} < L a^{+ 3}

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C e^{+ 3} < Y b^{+ 3} < P m^{+ 3} < L a^{+ 3}

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Y b^{+ 3} < P m^{+ 3} < L a^{+ 3} < C e^{+ 3}

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P m^{+ 3} < L a^{+ 3} < C e^{+ 3} < Y b^{+ 3}

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Solution

The correct option is A $Y b^{+ 3} < P m^{+ 3} < C e^{+ 3} < L a^{+ 3}$
In Lanthanides there is a regular decrease in atomic radii as well as ionic radii in trivalent ions the atomic number increases from $C e$ to $L u$ . This decrease in size of atoms and ions called lanthanide contraction. Although the atomic radii shows some irregularities but ionic radii decreases from $L a$ to $L u$ . Thus the correct order is,
$\begin{matrix} Y b^{+ 3} < & P m^{+ 3} < & C e^{+ 3} < & L a^{+ 3} 86.8 p m & 97 p m & 102 p m & 103 p m \end{matrix}$

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