Arrange the compounds I, II and III in decreasing order of their heats of combustion:
A
II > I > III
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B
I > II > III
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C
III > II > I
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D
III > I > II
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Solution
The correct option is C III > II > I
High ring strain will have less heat of combustion.
Order of heat of combustion: III>II>I, because ring strain is in the order I>II>III i.e. 5−membered ring strain is highest and as result it will have the lowest heat of combustion.