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Question

Arrange the compounds I, II and III in decreasing order of their heats of combustion:
989053_2d39f65912674c32971f1665184e280f.png

A
II > I > III
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B
I > II > III
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C
III > II > I
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D
III > I > II
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Solution

The correct option is C III > II > I
High ring strain will have less heat of combustion.
Order of heat of combustion: III>II>I, because ring strain is in the order I>II>III i.e. 5membered ring strain is highest and as result it will have the lowest heat of combustion.

1116703_989053_ans_014af2d6b3664085943f451cd6822276.png

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