Question

Arrange the descending order of fractions.

$\frac{5}{6},\frac{4}{15},\frac{8}{9}and\frac{1}{3}$

Answer 1

Explanation:

we have, $\frac{5}{6},\frac{4}{15},\frac{8}{9},\frac{1}{3}$

LCM of denominators $6,15,9$ and $3=$$2\times 3\times 3\times 5=90$ ( on taking L.C.M of denominators )

Convert each of the given fraction into an equivalent fraction with denominator $90$

$$\begin{gathered} \frac{5}{6}=\frac{5\times 15}{6\times 15}=\frac{75}{90},\frac{4}{15}=\frac{4\times 6}{15\times 6}=\frac{24}{90}, \\ \frac{8}{9}=\frac{8\times 10}{9\times 10}=\frac{80}{90}and\frac{1}{3}=\frac{1\times 30}{3\times 30}=\frac{30}{90} \end{gathered}$$

Clearly , $\frac{80}{90}>\frac{75}{90}>\frac{30}{90}>\frac{24}{90}$ $\Rightarrow \frac{8}{9}>\frac{5}{6}>\frac{1}{3}>\frac{4}{15}$

Hence, descending order of given fractions are $\frac{8}{9}>\frac{5}{6}>\frac{1}{3}>\frac{4}{15}$