Question

Arrange the descending order of fractions.

$\frac{7}{9},\frac{5}{12},\frac{11}{18}and\frac{17}{36}$

Answer 1

Explanation:

we have, $\frac{7}{9},\frac{5}{12},\frac{11}{18},\frac{17}{36}$

LCM of denominators $9,12,18$ and $36=$$2\times 2\times 3\times 3=36$ ( on taking L.C.M of denominators )

Converting each of the given fraction into an equivalent fraction with denominator $36$.

$$\begin{gathered} \frac{7}{9}=\frac{7\times 4}{9\times 4}=\frac{28}{36},\frac{5}{12}=\frac{5\times 3}{12\times 3}=\frac{15}{36}, \\ \frac{11}{18}=\frac{11\times 2}{18\times 2}=\frac{22}{36}and\frac{17}{36}=\frac{17\times 1}{36\times 1}=\frac{17}{36} \end{gathered}$$

Clearly , $\frac{28}{36}>\frac{22}{36}>\frac{17}{36}>\frac{15}{36}$ $\Rightarrow \frac{7}{9}>\frac{11}{18}>\frac{17}{36}>\frac{5}{12}$

Hence, descending order of given fractions are $\frac{7}{9}>\frac{11}{18}>\frac{17}{36}>\frac{5}{12}$.