Arrange the electron affinity of the following in decreasing order.

C l > F > B r > I

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C l > B r > F > I

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C l > B r > I > F

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C l > I > F > B r

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Solution

The correct option is B $C l > F > B r > I$
Electron affinity is the energy which is associated with the addition of an electron.
As we go down the group electron affinity is decreased because their shells increase and the election held by the nucleus decreases.
There are some exceptions also.
So in this case, trends should be $F^{-} > {C l}^{-} > {B r}^{-} > I^{-}$
But $F^{-}$ having small size and having 2s 2p orbital there is higher electron -electron repulsions. in smaller 2p orbital where as in ${C l}^{-}$ outermost orbital 3p and in this case repulsion will be less.
So the trend is $C l > F > B r > I$

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