Arrange the following according to the increasing order of the melting point.
I. Pentane II. Hexane
III. Heptane IV. Octane

I < I I < I I I < I V

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I > I I < I I I < I V

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I > I I > I I I > I V

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I < I I > I I I > I V

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Solution

The correct option is A $I < I I < I I I < I V$
As the molecular weight increases, the melting point increases. This result is because of stronger van der Waals forces.

Hence, the correct order of the melting points is $I (p e n t a n e) < I I (h e x a n e) < I I I (h e p t a n e) < I V (o c t a n e)$ .

So, the correct option is $A .$

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Arrange the following according to the increasing order of the melting point.I. Pentane II. Hexane III. Heptane IV. Octane

The correct option is A I<II<III<IVAs the molecular weight increases, the melting point increases. This result is because of stronger van der Waals forces. Hence, the correct order of the melting points is I(pentane)<II(hexane)<III(heptane)<IV(octane). So, the correct option is A.

Arrange the following according to the increasing order of the melting point.
I. Pentane II. Hexane
III. Heptane IV. Octane