Arrange the following acids in increasing order of their acid strength:
$I . H C l O_{4} I I . H_{2} {S O}_{4} I I I . H_{3} {P O}_{4}$

I I I < I I < I

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I < I I < I I I

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I I < I I I < I

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I I I < I < I I

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Solution

The correct option is A $I I I < I I < I$
In case of oxyacids as the number of oxygen bonded to central metal atom increases, the oxidation state of central atom increases which results in weakening of $O - H$ bond so increases acidic strength.
So $H_{3} P O_{4} < H_{2} S O_{4} < H C l O_{4}$ .

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