Arrange the following alcohols in decreasing order of the ease of ionization under acidic conditions.
A
I > III > II
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B
I > II > III
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C
II > III > I
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D
II > I > III
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Solution
The correct option is C II > III > I After dehydration carbocations are formed. the stability order is given by aromatic>non-aromatic > anti-aromatic. Hence correct stability order is II>III>I