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Question

Arrange the following alcohols in order of increasing ease of dehydration
CH3CH2OH C6H5CH2OH
I II

Cl3CCH2OH F3CCH2OH
​ III IV


A

II < I < IV < III

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B

IV < III < II < I

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C

IV < III < I < II

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D

II < I < III < IV

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Solution

The correct option is C

IV < III < I < II


Higher the stability of the carbocation , more easily it is formed and more will be the ease of its dehydration. Stability of the carbocations of the corresponding alcohol is

F3CCH2OH<Cl3CCH2OH<H3CCH2OH<C6H5CH2OH (Ease~of~dehydration)


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