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Question

Arrange the following alcohols in order of increasing reactivity towards sodium metal.
(i) (CH3)3C−OH (ii) (CH3)2CH−OH (iii) CH3CH2OH

A
(iii) < (ii) < (i)
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B
(ii) < (i) < (iii)
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C
(i) < (ii) < (iii)
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D
(iii) < (i) < (ii)
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Solution

The correct option is C (i) < (ii) < (iii)
Sodium metal replaces hydrogen of OH bond. It means higher the replacability of hydrogen of -OH or acidity of the moleucle, higher will be the reactivity with sodium metal.
More the number of methyl groups (electrons releasing) lesser will be the acidity. Hence the reactivity towards sodium metal will be tertiary alcohol < secondary alcohol < primary alcohol

Hence, the correct answer is option (c).

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