Arrange the following alkali metal carbonates in increasing order of their covalent character:
$R b_{2} C O_{3}, C s_{2} C O_{3}, L i_{2} C O_{3}, N a_{2} C O_{3}, K_{2} C O_{3}$

C s_{2} C O_{3} < R b_{2} C O_{3} < K_{2} C O_{3} < N a_{2} C O_{3} < L i_{2} C O_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

L i_{2} C O_{3} < N a_{2} C O_{3} < K_{2} C O_{3} < R b_{2} C O_{3} < C s_{2} C O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

R b_{2} C O_{3} < C s_{2} C O_{3} < L i_{2} C O_{3} < N a_{2} C O_{3} < K_{2} C O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $C s_{2} C O_{3} < R b_{2} C O_{3} < K_{2} C O_{3} < N a_{2} C O_{3} < L i_{2} C O_{3}$
Covalent character of carbonates of a particular group decreases due to increase in atomic size. Hence, ionic nature increases. It decreases from Li to Cs.

Thus, the correct order of covalent nature of carbonates of IA group elements is:
$C s_{2} C O_{3} < R b_{2} C O_{3} < K_{2} C O_{3} < N a_{2} C O_{3} < L i_{2} C O_{3}$
Hence, option A is correct.

Suggest Corrections