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Question
Arrange the following alkyl halides in decreasing order of the rate of β-elimination reaction with alcoholic KOH.
CH3CH2CH2Br(i) CH3−CH−CH2Br | CH3(ii) CH3−CH2−CH−CH3|Br(iii)
Arrange the following alkyl halides in decreasing order of the rate of β-elimination reaction with alcoholic KOH.
CH3CH2CH2Br(i) CH3−CH−CH2Br | CH3(ii) CH3−CH2−CH−CH3|Br(iii)
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Solution
The correct option is B (iii)>(i)>(ii)
CH3−CH2−CH2−Br CH3−CH|−CH2−Br CH3−CH2−CH|−CH3 (i) CH3 Br (ii) (iii)(iii)>(i)>(ii)Decreasing order of rate of β-elimination reaction with alcoholic KOH .
CH3−CH2−CH2−Br CH3−CH|−CH2−Br CH3−CH2−CH|−CH3
(i) CH3 Br
(ii) (iii)
(iii)>(i)>(ii)
Decreasing order of rate of β-elimination reaction with alcoholic KOH .
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