wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Arrange the following alkyl halides in decreasing order of the rate of β-elimination reaction with alcoholic KOH.
(I) CH3H|C|CH3CH2Br
(II) CH3CH2Br
(III) CH3CH2CH2Br

A
I>II>III
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
III>II>I
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
II>III>I
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
I>III>II
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D I>III>II
More the number of β- substituents (alkyl groups), more stable alkene it will form on β- elimination and more will be the reactivity.
Hence, the decreasing order of the rate of β-elimination reaction with alcoholic KOH is
I2βsubstituents>III1βsubstituents>II0βsubstituents.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
E2 Mechanism
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon