Arrange the following ascending order : 48.057 , 40.507 , 40.7 , 40.5 Two adjacent angles of a parallelogram are in the ratio 2;3. find the measure of each angles

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Solution

Ascending order
$\Rightarrow 40.5, 40.507, 40.7, 48.057$
Let two adjacent angles be $2 x$ and $3 x$
Sum of angles $360 °$
$2 \times (2 x + 3 x) = 360 ° 10 x = 360 ° x = 36 ° 2 x = 72 °, 3 x = 108 °$

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The measure of two adjacent angle of a parallelogram are in the ratio $3 : 2$ to find the measure of each of the angle of the parallelogram

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