Arrange the following atoms in increasing order of density: Na,Al,Fe,Pb
A
Pb>Fe>Al>Na
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B
Fe>Pb>Al>Na
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C
Al>Fe>Pb>Na
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D
Al>Pb>Fe>Na
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Solution
The correct option is APb>Fe>Al>Na The increasing order of density is Na < Al < Fe < Pb. The atomic mass of Al (27) is higher than the atomic mass of Na (23). The atomic volume of Na is higher than the atomic volume of Al (as the effective nuclear charge of Al is higher than the effective nuclear charge of Na). Hence, the density of Al is higher than the density of Na.