Arrange the following bonds according to their average bond energies in descending order: C−Cl,C−Br,C−F,C−I
A
C−Cl>C−Br>C−I>C−F
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
C−Br>C−I>C−Cl>C−F
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
C−I>C−Br>C−Cl>C−F
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
C−F>C−Cl>C−Br>C−I
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is DC−F>C−Cl>C−Br>C−I In C−F there is 2p−2p overlapping involved, in C−Cl the overlapping involved is 2p−3p whereas for C−Br and C−I the overlappings involved are 2p−4p and 2p−5p respectively. The bond length for the various type of overlappings can be given as: 2p−2p<2p−3p<2p−4p<2p−5p. As we know that Bond energy α1Bond length The order of bond energy comes out: C−F>C−Cl>C−Br>C−I