Arrange the following bonds according to their average bond energies in descending order: $C - Cl, C - Br, C - F, C - I$

$C - Cl > C - Br > C - I > C - F$

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$C - Br > C - I > C - Cl > C - F$

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$C - I > C - Br > C - Cl > C - F$

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$C - F > C - Cl > C - Br > C - I$

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Solution

The correct option is D
$C - F > C - Cl > C - Br > C - I$

Explanation for the correct option:
In $C - F$ there is $2 p - 2 p$ overlapping involved, this is a strong overlapping situation because both participating orbitals have the same symmetry and energy.
In $C - Cl$ the overlapping involved is $2 p - 3 p$ , whereas in $C - Br$ and $C - I$ the overlapping involved are $2 p - 4 p$ and $2 p - 5 p$ respectively. The bond length for the various type of overlapping can be given as: $2 p - 2 p < 2 p - 3 p < 2 p - 4 p < 2 p - 5 p .$
As we know, Bond energy $α$ $\frac{1}{Bond Length}$
The correct sequence of bond energy is $C - F > C - Cl > C - Br > C - I$
So, option (D) is correct.

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Arrange the following bonds according to their average bond energies in descending order:C-Cl,C-Br,C-F,C-I

Arrange the following bonds according to their average bond energies in descending order: $C - Cl, C - Br, C - F, C - I$