Arrange the following: $C H_{3} C H_{2} C H_{2} C H_{2} C l$ (I), $C H_{3} C H_{2} C H C l - C H_{3}$ (II), $(C H_{3})_{2} C H C H_{2} C l$ (III) and $(C H_{3})_{3} C - C l$ (IV) in order of decreasing tendency towards $S_{N} 2$ reaction

I > III > II > IV

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

III > IV > II > I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

II > I > III > IV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

IV > III > II > I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A I > III > II > IV
Reactivity decreases as the steric hinderance increases for $S_{N} 2$ reaction

Suggest Corrections

Similar questions

Arrange the following: $C H_{3} C H_{2} C H_{2} C l (I), C H_{3} C H_{2} C H C l C H_{3} (I I) {(C H_{3})}_{2} C H C H_{2} C l (I I I) a n d {(C H_{3})}_{3} C - C l (I V)$ in order of decreasing tendency towards $S N^{2}$ reaction

Q. Arrange the following:

C H_{3} C H_{2} C H_{2} C H_{2} C l

(I),

C H_{3} C H_{2} C H C l - C H_{3}

(II),

(C H_{3})_{2} C H C H_{2} C l

(III) and

(C H_{3})_{3} C - C l

(IV) in order of decreasing tendency towards

S_{N} 2

reaction

Q. Arrange the following compounds in their decreasing order of boiling points:

I . C_{9} H_{20} I I . C_{8} H_{18}

I I I . (C H_{3})_{2} C - (C H_{2})_{4} - C H_{3}

I V . C H_{3} - C H_{3} | C | C H_{3} - C H_{3} | C | C H_{3} - C H_{3}

Q. Arrange the following compounds in the order of decreasing tendency towards

S N_{2}

reaction.

C H_{3} C H_{2} C H_{2} C l . . . . . . . . . (i)

C H_{3} C H_{2} C H C l C H_{3} . . . . . . . (i i)

(C H_{3})_{2} C H C H_{2} C l . . . . . . . . (i i i)

(C H_{3})_{3} C - C l . . . . . . . . . . (i v)

Arrange the following alcohols in order of increasing ease of dehydration
$C H_{3} C H_{2} O H$ $C_{6} H_{5} C H_{2} O H$
I II

$C l_{3} C C H_{2} O H$ $F_{3} C C H_{2} O H$
III IV

Join BYJU'S Learning Program

Arrange the following: CH3CH2CH2CH2Cl (I), CH3CH2CHCl−CH3 (II), (CH3)2CHCH2Cl (III) and (CH3)3C−Cl (IV) in order of decreasing tendency towards SN2 reaction

The correct option is A I > III > II > IVReactivity decreases as the steric hinderance increases for SN2 reaction

Arrange the following: $C H_{3} C H_{2} C H_{2} C H_{2} C l$ (I), $C H_{3} C H_{2} C H C l - C H_{3}$ (II), $(C H_{3})_{2} C H C H_{2} C l$ (III) and $(C H_{3})_{3} C - C l$ (IV) in order of decreasing tendency towards $S_{N} 2$ reaction

The correct option is A I > III > II > IV
Reactivity decreases as the steric hinderance increases for $S_{N} 2$ reaction