Arrange the following: CH3CH2CH2CH2Cl (I), CH3CH2CHCl−CH3 (II), (CH3)2CHCH2Cl (III) and (CH3)3C−Cl (IV) in order of decreasing tendency towards SN2 reaction
A
I>III>II>IV
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B
III>IV>II>I
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C
II>I>III>IV
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D
IV>III>II>I
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Solution
The correct option is AI>III>II>IV
Reactivity decreases as the steric hinderance increases for SN2 reaction