Arrange the following compounds in correct order of acidic strength.

H C O O H > C H_{3} C O O H > C_{6} H_{5} O H > C_{2} H_{5} - O H

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{C H}_{3} C O O H > H C O O H > C_{6} H_{5} O H > C_{2} H_{5} - O H

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C_{6} H_{5} O H > H C O O H > C H_{3} C O O H > C_{2} H_{5} - O H

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None of these

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Solution

The correct option is D $H C O O H > C H_{3} C O O H > C_{6} H_{5} O H > C_{2} H_{5} - O H$
The correct increasing order of acidic strength is given by $C_{2} H_{5} O H < C_{6} H_{5} O H < {C H}_{3} {C O}_{2} H < {H C O}_{2} H$ . When substituent group is electron releasing, then the acidity decreases. Hence ${C H}_{3} {C O}_{2} H$ is less acidic than ${H C O}_{2} H$ .
As both $C_{2} H_{5} O H$ & $C_{2} H_{5} O H$ come under alcohols $C_{2} H_{5} O H$ is acidic acid due to resonance stabilized $C_{6} H_{5} O^{-}$ ion.

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Q. The pH of 1N aqueous solutions of

H C l, C H_{3} C O O H a n d H C O O H

follows the order

C_{2} H_{5} - O - C_{2} H_{5} + H I ? \to C_{2} H_{5} - O H + C_{2} H_{5} - I

Identify the reaction condition, in which reaction occur.

Q. For the compounds,
I) HCOOH II)

C H_{3} C O O H

III)

C H_{3} C H_{2} C O O H

IV)

C_{6} H_{5} C O O H

The correct order of decreasing acidity is :

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