Arrange the following compounds in increasing order of boiling points.
I: $3$ -methyl pentane II: $3$ -chloropentane
III: $3$ -bromopentane IV: $3, 3$ -dichloropentane

I < I I I < I I < I V

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I < I V < I I I < I I

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I < I I < I I I < I V

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I < I I I < I V < I I

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Solution

The correct option is C $I < I I < I I I < I V$
The increasing order of the boiling points is $I$ ( $3$ -methyl pentane) < $I I$ ( $3$ -chloropentane) < $I I I$ ( $3$ -bromopentane)
$<$ IV $($ 3,3-dichloropentane). Higher is the molecular weight, higher will be the boiling point.

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