Question

Arrange the following compounds in increasing order of their boiling points.

• A. $\left(b\right)<\left(a\right)<\left(c\right)$
• B. $\left(a\right)<\left(b\right)<\left(c\right)$
• C. $\left(c\right)<\left(a\right)<\left(b\right)$
• D. $\left(c\right)<\left(b\right)<\left(a\right)$

Answer 1

Answer: (C)

$\left(c\right)<\left(a\right)<\left(b\right)$

The increasing order of the boiling points is $\left(c\right)<\left(a\right)<\left(b\right)$.

As the branching of alkyl halide increases, the boiling point decreases.

Thus, the boiling point of tert butyl bromide is lowest and the boiling point of n butyl bromide is highest.

Option C is correct.